When two 10 ohm resistors are connected in Parallel, what is the net result?

When two 10 ohm resistors are connected in Parallel, what is the net result?

• A. 10 ohms
• B. 15 ohms
• C. 5 ohms
• D. 20 ohms

Answer: (C)

When two 10 ohm resistors are connected in parallel, the total or equivalent resistance can be calculated using the formula for parallel resistors, which is: 1/R_total = 1/R1 + 1/R2 In this case: 1/R_total = 1/10 + 1/10 This simplifies to: 1/R_total = 2/10 To find R_total, you take the reciprocal of the result: R_total = 10/2 = 5 ohms Thus, the net result of connecting two 10 ohm resistors in parallel is indeed 5 ohms. This outcome occurs because parallel connections decrease total resistance, allowing more paths for current to flow, making it easier for current to pass through the circuit.

When two 10 ohm resistors are connected in parallel, the total or equivalent resistance can be calculated using the formula for parallel resistors, which is:

1/R_total = 1/R1 + 1/R2

In this case:

1/R_total = 1/10 + 1/10

This simplifies to:

1/R_total = 2/10

To find R_total, you take the reciprocal of the result:

R_total = 10/2 = 5 ohms

Thus, the net result of connecting two 10 ohm resistors in parallel is indeed 5 ohms. This outcome occurs because parallel connections decrease total resistance, allowing more paths for current to flow, making it easier for current to pass through the circuit.